Codehs 8.1.5 Manipulating 2d Arrays: |verified|
I'll give you the exact solution for your version!
: The "last" element in a row isn’t always at the same index if the rows have different lengths. Use array[row].length - 1 to find the last index safely. array.length : Gives you the number of array[0].length : Gives you the number of in the first row. Writing an updateValue
function manipulate(arr, threshold) for (let row = 0; row < arr.length; row++) for (let col = 0; col < arr[row].length; col++) if (arr[row][col] > threshold) arr[row][col] = arr[row][col] * 2; Codehs 8.1.5 Manipulating 2d Arrays
manipulate(testArray, 5); // Threshold = 5
In this guide, we will break down exactly what 8.1.5 asks, the core logic required to pass the autograder, and the deeper programming patterns that will help you manipulate any two-dimensional array in your future projects. I'll give you the exact solution for your version
To do this efficiently, you need .
Notice grid.length gives the number of rows, while grid[r].length gives the number of columns in that specific row. Using .length instead of hard-coded numbers makes your code flexible and is a requirement for best practices in AP Computer Science A. Notice grid
In the typical CodeHS progression (specifically in the AP Computer Science A or Introduction to Java tracks), is a coding exercise found in the "2D Arrays" module. By this point, you already know how to declare ( int[][] matrix = new int[3][3]; ) and traverse a 2D array using nested loops. However, 8.1.5 asks you to go a step further: modify the array in place based on specific conditions.
