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[ 2(1 - \cos^2 x) - \cos x - 1 = 0 ] [ 2 - 2\cos^2 x - \cos x - 1 = 0 ] [ -2\cos^2 x - \cos x + 1 = 0 ] Multiply by -1: [ 2\cos^2 x + \cos x - 1 = 0 ]
Resolver es como ser un detective que busca un ángulo misterioso (
Solve: ( 2\sin^2 x - \cos x - 1 = 0 ) for ( x \in [0, 2\pi) ). [ 2(1 - \cos^2 x) - \cos x
Remember that trigonometric functions are periodic. Always add ) to represent all possible turns. Solved Exercise: The Quadratic Style Step 1: Get everything in terms of (Multiply by -1 to clean it up) Step 2: Solve the quadratic . The equation is Using the quadratic formula: Step 3: Find the angles (1st Quadrant) (2nd Quadrant, because Final Solutions: Pro-Tip: Watch out for "False Friends"
Resuelve ( \cos(x) = -\frac\sqrt22 ) en ([0, 2\pi)). Solved Exercise: The Quadratic Style Step 1: Get
So:
Vamos a clasificar los ejercicios por dificultad para abordarlos de forma progresiva. [ 2(1 - \cos^2 x) - \cos x
¿Necesitas más ejercicios resueltos de trigonometría para 1º Bachillerato? Déjamelo en los comentarios.
Lee bien el enunciado. Si te piden la respuesta en radianes, recuerda que
Ecuaciones Trigonométricas: Guía Completa con Ejercicios Resueltos (1º Bachillerato)