Circuit Training Integrals Of Rational - Expressions [upd]

In a mathematical circuit, students start with problem #1 in one box, solve it, and then "hunt" for their answer in the heading of another box. That new box becomes problem #2. The activity is complete only when the final answer leads them back to the very first box.

In a circuit, this answer might lead them to a problem involving an inverse trig function, signaling a shift in technique required for the next station. Circuit Training Integrals Of Rational Expressions

Have two different-looking answers that are actually equivalent (e.g., ln|(x+2)/(x-1)| vs. ln|x+2| – ln|x-1|). The circuit requires recognizing algebraic equivalence. In a mathematical circuit, students start with problem